3.5 At room temperature (27.0 °C) the resistance of a heating element is 100 Ω. What is the temperature of the element if the resistance is found to be 117 Ω, given that the temperature coefficient of the material of the resistor is 1.70 * 10–4 °C–1.

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8 months ago

3.5 Let T be the room temperature and R be the resistance at room temperature and T1 be the required temperature and R1 be the resistance at that temperature and α be the coefficient of resistor.

We have:

T = 27 ?, R = 100 Ω, T1 = ?, R1 = 117 Ω, α = 1.70 *10-4 ° C-1

We know the relation of α can be given as

α = R1-RR(T1-T) = 117-100100(T1-27) = 1.7

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Physics Ncert Solutions Class 12th 2023

Physics Ncert Solutions Class 12th 2023

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