4.28 A galvanometer coil has a resistance of 15 Ω and the meter shows full scale deflection for a current of 4 mA. How will you convert the meter into an ammeter of range 0 to 6 A?

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    Answered by

    Payal Gupta | Contributor-Level 10

    5 months ago

    4.28 Resistance of the galvanometer coil, G = 15 Ω

    Current for which galvanometer shows full deflection, I g = 4 mA = 4 × 10 - 3 A

    Range of ammeter has to be converted from 0 to 6 A, hence I = 6 A

    A shunt resistor S is to be connected in parallel with the galvanometer to convert it to an ammeter. The value of S is given as

    S = 10 mΩ

    Hence, a shunt resistor of 10 mΩ is to be connected to galvanometer to convert it to an ammeter.

     

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