5.13 A short bar magnet placed in a horizontal plane has its axis aligned along the magnetic north-south direction. Null points are found on the axis of the magnet at 14 cm from the centre of the magnet. The earth's magnetic field at the place is 0.36 G and the angle of dip is zero. What is the total magnetic field on the normal bisector of the magnet at the same distance as the null–point (i.e., 14 cm) from the centre of the magnet? (At null points, field due to a magnet is equal and opposite to the horizontal component of earth's magnetic field.)

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8 months ago

5.13 Earth's magnetic field at the given place, H = 0.36 G

The magnetic field at a distance d, on the axis of the magnet is given as

B 1 = μ 0 4 π 2 M d 3 = H ………………..(1)

where μ 0 = Permeability of free space = 4 π * 10 - 7 T m A - 1 and M = magnetic moment

Total magnetic field, B = B 1 + B 2 = H + H 2 = 0.36 + 0.18 = 0.54 G

Therefore, the mag

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Physics Ncert Solutions Class 12th 2023

Physics Ncert Solutions Class 12th 2023

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