5.7 A bar magnet of magnetic moment 1.5 J T–1 lies aligned with the direction of a uniform magnetic field of 0.22 T.
(a) What is the amount of work required by an external torque to turn the magnet so as to align its magnetic moment: (i) normal to the field direction, (ii) opposite to the field direction?
(b) What is the torque on the magnet in cases (i) and (ii)?
5.7 A bar magnet of magnetic moment 1.5 J T–1 lies aligned with the direction of a uniform magnetic field of 0.22 T.
(a) What is the amount of work required by an external torque to turn the magnet so as to align its magnetic moment: (i) normal to the field direction, (ii) opposite to the field direction?
(b) What is the torque on the magnet in cases (i) and (ii)?
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1 Answer
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5.7 Magnetic moment, M = 1.5 J/T
Magnetic field strength, B = 0.22 T
Initial angle between the axis and the magnetic field, = 0 and the final angle, = 90
Work required to make the magnetic moment normal to the direction of the magnetic field is given as:
W = -MB( cos cos ) = - 1.5 - cos 0 ) = 0.33 J
Initial angle between the axis and the magnetic field, = 0 and the final angle, = 180
Work required to make the magnetic moment normal to the direction of the magnetic field is given as:
W = -MB( cos cos ) = - 1.5 - cos 0 ) = 0.33 J
For case
Torque , here = = 90
= 1.5 = 0.33 J
Torque , here = = 180
= 1.5 =
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