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512 identical drops of mercury are charged to a potential of 2V each. The drops are joined to form a single drop. The potential of this drop is ……………. V.

0 2 Views | Posted 2 weeks ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    2 weeks ago

    Let the charge of on each drop be q and radius of each drop be r.

      k q r = 2

    When all drops are joined, radius,

    r ' = ( 5 1 2 ) 1 3 r = 8 r

    Potential of the new drop,

    V = k . 5 1 2 q 8 r = 6 4 k q r = 1 2 8 V

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