9.17 (a) Figure 9.32 shows a cross-section of a 'light pipe' made of a glass fibre of refractive index 1.68. The outer covering of the pipe is made of a material of refractive index 1.44. What is the range of the angles of the incident rays with the axis of the pipe for which total reflections inside the pipe take place, as shown in the figure.

(b) What is the answer if there is no outer covering of the pipe?

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Payal Gupta | Contributor-Level 10

8 months ago

9.17 Refractive index of the glass fibre, $μ_{1}$ = 1.68

Refractive index of outer covering of the pipe, $μ_{2}$ = 1.44

Given:-

Angle of incidence = i, Angle of refraction = r, Angle of incidence at the interface = i'

The refractive index of the inner core-outer core interface, $μ$ is given as

$μ = \frac{μ_{2}}{μ_{1}}$ = $\frac{1}{\sin ? i'}$

$\frac{1}{\sin ? i'} = \frac{1.44}{1.68}$ or $\sin ? i'$ = $\frac{1.44}{1.68}$

i' = 59 $°$

For the c

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