A 100 kg gun fires a ball of 1kg horizontally from a cliff of height 500m. It falls on the ground at a distance of 400m from the bottom of the cliff. Find the recoil velocity of the gun. (acceleration due to gravity = 10 m/s^-2)

This is a Short Answer type Questions as classified in NCERT Exemplar

Explanation- mass of gun =100kg

Mass of ball =1kg and height of cliff = 500m

So horizontal distance travelled by the ball is x = 400m

So h =1/2gt²

500= $\frac{1}{2}10\left(t\right)$ ² so t= 10s

X=ut then u= 400/10=40m/s

 According to principle of conservation pf momentum

Mv=mu

V= 40/100= 0.4m/s

<p>This is a Short Answer type Questions as classified in NCERT Exemplar</p><p><strong><span lang="EN-IN">Explanation-&nbsp;</span></strong><span lang="EN-IN">mass of gun =100kg</span></p><div class="photo-widget-full"><div class="figure"><picture><source srcset="" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/1751023392phpJDFbjz.jpeg" alt="" width="301" height="219" loading="lazy"></picture></div></div><p><span lang="EN-IN">Mass of ball =1kg and height of cliff = 500m</span></p><p><span lang="EN-IN">So horizontal distance travelled by the ball is x = 400m</span></p><p><span lang="EN-IN">So h =1/2gt²</span></p><p><span lang="EN-IN">500=<span class="mathml" contenteditable="false"> <math> <mfrac> <mrow> <mrow> <mn>1</mn> </mrow> </mrow> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> </mfrac> <mn>10</mn> <mo> (</mo> <mi>t</mi> <mo>)</mo> </math> </span></span>^{<span lang="EN-IN">2</span>}<span lang="EN-IN"> so t= 10s</span></p><p><span lang="EN-IN">X=ut then u= 400/10=40m/s</span></p><p><span lang="EN-IN">&nbsp;According to principle of conservation pf momentum</span></p><p><span lang="EN-IN">Mv=mu</span></p><p><span lang="EN-IN">V= 40/100= 0.4m/s</span></p>

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