A 110 V, 50Hz, AC source is connected in the circuit (as shown in figure). The current through the resistance $55\Omega ,$  at resonance in the circuit, will be__________A.

 

At Resonance

X_L = X_C

then l_L = l_C

Now phasor diagram

for L & C

So, Net current = zero

  $=\left(l_L+l_C\right)$  

Therefore current through R circuit at resonance will be zero

 

 

             

<p>At Resonance</p><p>X_L = X_C</p><p>then l_L = l_C</p><p>Now phasor diagram</p><p>for L &amp; C</p><p>So, Net current = zero</p><p>&nbsp;<span class="mathml" contenteditable="false"> <math> <mrow> <mo>=</mo> <mrow> <mo> (</mo> <mrow> <msub> <mrow> <mi>l</mi> </mrow> <mrow> <mi>L</mi> </mrow> </msub> <mo>+</mo> <msub> <mrow> <mi>l</mi> </mrow> <mrow> <mi>C</mi> </mrow> </msub> </mrow> <mo>)</mo> </mrow> </mrow> </math> </span>&nbsp;</p><p>Therefore current through R circuit at resonance will be zero</p><div class="photo-widget-full"><div class="figure"><div class="photo-widget-full"><div class="figure"><picture><source srcset="" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/1758015944phpQLgh8N.jpeg" alt="" width="193" height="125" loading="lazy"></picture></div></div><p>&nbsp;</p></div></div><p>&nbsp;</p><p>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</p>

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