A 220 V, 50 Hz AC source is connected to a 25 V, 5 W lamp and an additional resistance R in series (as shown in figure)

to run the lamp at its peak brightness, then the value of R (in ohm) will be__________.

8 Views|Posted 6 months ago
Asked by Shiksha User
1 Answer
V
6 months ago

for lamp,   P = v 2 R

R = 2 5 * 2 5 5 = 1 2 5 Ω              

l m a x = v R = 2 5 1 2 5 = 1 5 A    

I m a x = 2 2 0 1 2 5 + R = 1 5

1 1 0 0 = 1 2 5 + R        

R = 975  Ω

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