A balloon was moving upwards with a uniform velocity of 10 m/s. An object of finite mass is dropped from the balloon when it was at a height of 75 m from the ground level. The height of the balloon from the ground when object strikes the ground was around :
(takes the value of g as 10 m/s²)

Option 1 -

250 m

Option 2 -

300 m

Option 3 -

200 m

Option 4 -

125 m

0 2 Views | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    a month ago
    Correct Option - 4


    Detailed Solution:

    Body is dropped from height 75m with initial velocity (upward) 10m/s
    So, s = ut + ½ at²
    -75 = 10t - ½ gt²
    5t² - 10t - 75 = 0
    By solving t = 5 sec.
    In 5sec. balloon covered
    h = 10 × 5 = 50m
    Now height of balloon = 75 + 50 = 125m

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