A beam of electrons of energy E scatters from a target having atomic spacing of IÅ °. The first maximum intensity occurs at θ = 60°. Then E (in eV) is (Planck constant h = electron mass m = 9.1 × 10?³¹ kg )
A beam of electrons of energy E scatters from a target having atomic spacing of IÅ °. The first maximum intensity occurs at θ = 60°. Then E (in eV) is (Planck constant h = electron mass m = 9.1 × 10?³¹ kg )
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1 Answer
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We know, P = √2Em and λ = h/√2Em
For 1st maxima, 2nd sinθ = λ
Put (1) and get the answer
E = 50.47eV.
B = µ? I (200)/2R? R? = 20 cm; R? = 1 cm
e = -dΦ/dt = π (R? )² (500) dB/dt
= π (R? )² (500) (µ? I/2R? ²) (200) (10t-2)
= π (1/10000) (500) (200) (µ? ) (8) (5)/ (2)
= 16π² x 10 x 5 x 10?
= 800π² x 10?
e = 0.7887mv
4/x = 0.8; x = 5.
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