A beam of plane polarized light of large cross-sectional area and uniform intensity of 3.3Wm⁻² falls normally on a polarizer (cross sectional area 3 × 10⁻⁴ m² ) which rotates about its axis with an angular speed of 31.4rad/s. The energy of light passing through the polariser per revolution, is close to:
A beam of plane polarized light of large cross-sectional area and uniform intensity of 3.3Wm⁻² falls normally on a polarizer (cross sectional area 3 × 10⁻⁴ m² ) which rotates about its axis with an angular speed of 31.4rad/s. The energy of light passing through the polariser per revolution, is close to:
Option 1 -
1.0 * 10⁻⁵ J
Option 2 -
1.5 * 10⁻⁴ J
Option 3 -
5.0 * 10⁻⁴ J
Option 4 -
1.0 * 10⁻⁴ J
Asked by Shiksha User
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1 Answer
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Correct Option - 4
Detailed Solution:E = (I)(t)(A)(cos²θ)
⇒ (3.3) (2π / [31.4]) [3 × 10?] × 1/2
⇒ 0.99 × 10?
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