A beam of protons with speed 4 × 10⁵ ms⁻¹ enters a uniform magnetic field of 0.3 T at an angle of 60° to the magnetic field. The pitch of the resulting helical path of protons is close to: (Mass of the proton = 1.67 × 10⁻²⁷ kg, charge of the proton = 1.69 × 10⁻¹⁹ C)
A beam of protons with speed 4 × 10⁵ ms⁻¹ enters a uniform magnetic field of 0.3 T at an angle of 60° to the magnetic field. The pitch of the resulting helical path of protons is close to: (Mass of the proton = 1.67 × 10⁻²⁷ kg, charge of the proton = 1.69 × 10⁻¹⁹ C)
Option 1 -
2 cm
Option 2 -
4 cm
Option 3 -
12 cm
Option 4 -
5 cm
Asked by Shiksha User
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1 Answer
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Correct Option - 2
Detailed Solution:Pitch = (Vcosθ)T = (Vcosθ)2πm/eB
= (4×10? cos60°) (2π (1.67×10? ²? )/ (0.3×10? ¹? ×1.69×10¹? )
= 4 cm
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