A block of mass M placed inside a box descends vertically with acceleration ‘a’. The block exerts a force equal to one-fourth of its weight on the floor of the box. The value of ‘a’ will be

Correct Option - 3


Detailed Solution:

According to Newton’s law of motion, we can write

ma = mg – N = mg $\frac{mg}{4}=\frac{3mg}{4}$

$\Rightarrow a=\frac{3g}{4}$

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