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Class 11thPhysics OscillationsPhysicsSimple Harmonic Motion

A body is executing simple harmonic motion with frequency ' n ', the frequency of its potential energy is:

Option 1 - <p><span class="mathml" contenteditable="false"> <math> <mi mathvariant="normal">n</mi> </math> </span></p>
Option 2 - <p><span class="mathml" contenteditable="false"> <math> <mn>2</mn> <mi mathvariant="normal">n</mi> </math> </span></p>
Option 3 - <p><span class="mathml" contenteditable="false"> <math> <mn>3</mn> <mi>n</mi> </math> </span></p>
Option 4 - <p><span class="mathml" contenteditable="false"> <math> <mn>4</mn> <mi mathvariant="normal">n</mi> </math> </span></p>
2 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
A
5 months ago
Correct Option - 2
Detailed Solution:

Displacement equation of SHM of frequency ' n  '

x = A s i n ? ( ω t ) = A s i n ? ( 2 π n t )

Now,

Potential energy U = 1 2 k x 2 = 1 2 K A 2 s i n 2 ? 2 π n t

= 1 2 k A 2 1 - c o s ? 2 π 2 n t 2

So frequency of potential energy = 2 n

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