A body of mass m is attached to one end of a massless spring which is suspended vertically from a fixed point. The mass is held in hand so that the spring is neither stretched nor compressed. Suddenly the support of the hand is removed. The lowest position attained by the mass during oscillation is 4cm below the point, where it was held in hand. (a) What is the amplitude of oscillation? (b) Find the frequency of oscillation?
A body of mass m is attached to one end of a massless spring which is suspended vertically from a fixed point. The mass is held in hand so that the spring is neither stretched nor compressed. Suddenly the support of the hand is removed. The lowest position attained by the mass during oscillation is 4cm below the point, where it was held in hand. (a) What is the amplitude of oscillation? (b) Find the frequency of oscillation?
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Velocity of block in equilibrium, in first case,
Velocity of block in equilibrium, is second case,
From conservation of momentum,
Mv = (M + m) v’
f? = 300 Hz
3rd overtone = 7f? = 2100 Hz
Kindly consider the following figure
K = U
½ mω² (A² - x²) = ½ mω²x²
A² - x² = x²
A² = 2x²
x = ± A/√2
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Physics NCERT Exemplar Solutions Class 11th Chapter Fourteen 2025
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