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A bullet of 10g, moving with velocity v, collides head-on with the stationary bob of a pendulum and recoils with velocity 100 m/s. The length of the pendulum is 0.5m and mass of the bob is 1kg. The minimum value of v = _____m/s so that the pendulum describes a circle.

(Assume the string to be inextensible and g = 10 m/s2)

 

0 12 Views | Posted 2 months ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    2 months ago

    Velocity of bob after collision,

    v1 = 5 g R = 5 × 1 0 × 0 . 5 = 5 m / s

    From Conservation of Momentum,

    1 0 1 0 0 0 × v = − 1 0 1 0 0 0 × 1 0 0 + 1 × 5  

    ->v = 400 m/s  

     

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