A bullet of mass 0.1 kg is fired on a wooden block to pierce through it, but it stops after moving a distance of 50 cm into it. If the velocity of bullet before hitting the wood is 10m/s and slows down with uniform deceleration, then magnitude effective retarding force on the bullet is 'x' N. The value of 'x' to the nearest integer is----------.

0 3 Views | Posted a month ago
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  • R

    Answered by

    Raj Pandey | Contributor-Level 9

    a month ago

    Deceleration, a = u² / 2S = 10² / (2 × 0.5) = 100 m/s².
    Retarding force, F = MA = 0.1 × 100 = 10N

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