A butterfly is flying with a velocity $4 \sqrt[]{2} m / s$ in North – East direction. Wind is slowly blowing at 1 m/s from North to South. The resultant displacement of the butterfly in 3 seconds is:

Option 1 - 15m

Option 2 - 20m

Option 3 - 3m

Option 4 - <math> <mrow> <mn>1</mn> <mn>2</mn> <mroot> <mrow> <mn>2</mn> </mrow> <mrow></mrow> </mroot> <mi>m</mi> </mrow> </math>

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Answered by

Alok Kumar Singh | Contributor-Level 10

6 months ago

Correct Option - 1

Detailed Solution:

${\vec{v}}_{B W} = 4 \sqrt[]{2} (c o s 45 ° \hat{i} + s i n 45 ° \hat{j}) = 4 \hat{i} + 4 \hat{j}, a n d {\vec{v}}_{W g} = 0 \hat{i} - \hat{j}$

${\vec{v}}_{B g} = {\vec{v}}_{B W} + {\vec{v}}_{W g} = (4 \hat{i} + 4 \hat{j}) + (0 \hat{i} - \hat{j}) = 4 \hat{i} + 3 \hat{j}$

$| {\vec{v}}_{B g} | = 5 m / s \Rightarrow S p e e d o f B u t t e r f l y$

Magnitude of displacement of Butterfly = $| {\vec{v}}_{B g} | * t = 5 * 3 = 15 m$

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A butterfly is flying with a velocity 4 2 m / s in North – East direction. Wind is slowly blowing at 1 m/s from North to South. The resultant displacement of the butterfly in 3 seconds is:

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