A capacitor has some dielectric between its plates and the capacitor is connected to a DC source. The battery is now disconnected and then the dielectric is removed. State whether the capacitance, the energy stored in it, electric field, charge stored and the voltage will increase, decrease or remain constant.

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    Answered by

    Payal Gupta | Contributor-Level 10

    3 months ago

    This is a short answer type question as classified in NCERT Exemplar

    The capacitance of the parallel plate capacitor, with dielectric medium of dielectric constant K is given by, C=K? 0A/d

    The capacitance of the parallel plate capacitor decreases with the removal of dielectric medium.

    If we disconnect the battery from capacitor, then the charge stored will remain the same due to conservation of charge.

    The energy stored in an isolated charge capacitor  U =q2/2C  as q is constant, energy stored U ∝ 1/C .As C decreases with the removal of dielectric medium, therefore energy stored increases.

    The potential difference across the

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