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A carnot engine works between temperatures 327°C and 27°C. If the engine takes 1600 J of heat from the higher temperature reservoir, the work done by the engine per cycle (in Joule) is equal to ______.

0 2 Views | Posted 3 weeks ago
Asked by Shiksha User

  • 1 Answer

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    Answered by

    Vishal Baghel | Contributor-Level 10

    3 weeks ago

    (Q? - Q? )/Q? = (T? - T? )/T? ; Q = (300/600) × 1600 = 800 J
    work done = Q? - Q? = 1600 – 800 = 800J

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