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A Carnot's engine working between 400 K and 800 K has a work output of 1200J per cycle. The amount of heat energy supplied to the engine from the source in each cycle is:

Option 1 -

3200 J

Option 2 -

2400 J

Option 3 -

1800 J

Option 4 -

1600 J

0 2 Views | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    a month ago
    Correct Option - 2


    Detailed Solution:

    η = 1 - T_C / T_H

    η = 1 - 400/800 = 1 - ½ = ½

    η = W/Q_H ⇒ ½ = W/Q_H ⇒ Q_H = 2W = 2 × 1200 = 2400 J

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