A charged particle (mass m and charge q) moves along x axis with velocity V₀. When it passes through the origin it enters a region having uniform electric field E = -Ej which extends upto x = d. Equation of path of electron in the region x > d is:

Correct Option - 1


Detailed Solution:

x > d path is straight line
-y = 1/2 at²
x-d = V?t ⇒ t=(x-d)/V?
-y = 1/2 a((x-d)/V?)²
-y/at = (1/2at)(a²t²)
at = V?
(-y/at) = (d/2V?)
(x-d)/V? = d/V?
(-y - 1/2 a t²)/(at) = (x-d - V?t)/V?
y = (-qEd/mV?)(x/V? - d/2V?) ; y = (qEd/mV?²)(d/2 - x)

 

<div class="photo-widget-full"><div class="figure"><picture><source srcset="" media="(max-width: 500px)"></picture><p>x &gt; d path is straight line<br>-y = 1/2 at²<br>x-d = V?t ⇒ t=(x-d)/V?<br>-y = 1/2 a((x-d)/V?)²<br>-y/at = (1/2at)(a²t²)<br>at = V?<br>(-y/at) = (d/2V?)<br>(x-d)/V? = d/V?<br>(-y - 1/2 a t²)/(at) = (x-d - V?t)/V?<br>y = (-qEd/mV?)(x/V? - d/2V?) ; y = (qEd/mV?²)(d/2 - x)</p><picture><img src="https://images.shiksha.com/mediadata/images/1756116163phpegeUSl.jpeg" alt="" width="451" height="334" loading="lazy"></picture></div></div><p>&nbsp;</p>

0 Upvotes 0 Upvotes 0 Downvotes

• • Report Abuse
• Comment