A circuit element X when connected to an a.c. supply of peak voltage 100V given a peak current of 5A which is in phase with the voltage. A second element Y when connected to the same a.c. supply also gives the same value of peak current which lags behind the voltage by If X and Y are connected in series to the same supply, what will be the rms value of the current in ampere?
A circuit element X when connected to an a.c. supply of peak voltage 100V given a peak current of 5A which is in phase with the voltage. A second element Y when connected to the same a.c. supply also gives the same value of peak current which lags behind the voltage by If X and Y are connected in series to the same supply, what will be the rms value of the current in ampere?
Option 1 -
Option 2 -
Option 3 -
Option 4 -
-
1 Answer
-
Correct Option - 4
Detailed Solution:v = 100 sin
i =
i = 100 5sin &nb
...more
Similar Questions for you
At resonance VL = VC
On increasing XC decreases so Z decreases, current in circuit increases.
R =
L = 2 mH
E = 9V
Just after the switch ‘S’ is closed, the inductor acts as open circuit.
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 688k Reviews
- 1800k Answers