A circuit element X when connected to an a.c. supply of peak voltage 100V given a peak current of 5A which is in phase with the voltage. A second element Y when connected to the same a.c. supply also gives the same value of peak current which lags behind the voltage by  If X and Y are connected in series to the same supply, what will be the rms value of the current in ampere?

Option 1 -

1 0 2

Option 2 -

5 2

Option 3 -

5 2

Option 4 -

5 2

0 3 Views | Posted 2 months ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    2 months ago
    Correct Option - 4


    Detailed Solution:

    v = 100 sin ω t                                                             

    i 0 = 1 0 0 R x = 5 R x = 2 0 Ω               

    i = 5 s i n ( ω t π 2 )  

     i = 100 5sin ω t                             &nb

    ...more

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