A copper block of mass 5.0kg is heated to a temperature of $500 ° C$ and is placed on a large ice block. What is the maximum amount of ice that can melt?

[Specific heat of copper : 0.39 J g^-1 ⁰C^-1 and latent heat of fusion of water : 335 J g^-1]

Option 1 - 2.91 kg

Option 2 - 3.9 Kg

Option 3 - 4 Kg

Option 4 - 2 Kg

3 Views|Posted 6 months ago

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Answered by

Raj Pandey | Contributor-Level 9

6 months ago

Correct Option - 1

Detailed Solution:

Heat Released by block = Heat gain by large Ice block

$\Rightarrow m c Δ T = M_{i c e} L$

5 * 0.39 * 500 = m_ice * 335

$m_{i c e} = \frac{5 * 0.39 * 500}{335}$

= 2.91 kg

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A copper block of mass 5.0kg is heated to a temperature of 5 0 0 ° C and is placed on a large ice block. What is the maximum amount of ice that can melt? [Specific heat of copper : 0.39 J g-1 0C-1 and latent heat of fusion of water : 335 J g-1]