A cube of metal is subjected to a hydrostatic pressure 4GPa. The percentage change in the length of the side of the cube is close to: (Given bulk modulus of metal, B = 8 * 1010 Pa)

Option 1 - <p>0.6</p>
Option 2 - <p>5</p>
Option 3 - <p>1.67<br>&lt;!-- [if !supportLineBreakNewLine]--&gt;<br>&lt;!--[endif]--&gt;</p>
Option 4 - <p>20</p>
3 Views|Posted 5 months ago
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1 Answer
V
5 months ago
Correct Option - 3
Detailed Solution:

B (ΔV/V) = ΔP
ΔV/V = ΔP/B = (4 x 10? )/ (8 x 10¹? ) = 1/20
V = l³
dV = 3l² dl
dV/V = 3l²dl/l³ = 3dl/l
ΔV/V = 3 (Δl/l); 1/20 = 3 (Δl/l); ΔV/V = 1/60

% (Δl/l) = 100/60 = 1.67%

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Physics Mechanical Properties of Fluids 2025

Physics Mechanical Properties of Fluids 2025

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