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Magnetic Field due to a Current Element Physics Class 12th Physics Moving Charges and Magnetism

A current of 1.5 A is flowing through a triangle, of side 9cm each. The magnetic field at the centroid of the triangle is:

(Assume that the current is flowing in the clockwise direction.)

Option 1 -

$2 \sqrt[]{3} * 1 0^{- 7} T,$ outside the plane of triangle

Option 2 -

$2 \sqrt[]{3} * 1 0^{- 5} T,$ inside the plane of triangle

Option 3 -

3 * 10^-5 T, inside the plane of triangle

Option 4 -

3 * 10^-7 T, outside the plane of triangle

2 Views | Posted 2 months ago

Asked by Shiksha User

1 Answer

Answered by

Vishal Baghel | Contributor-Level 10

2 months ago

Correct Option - 3

Detailed Solution:

Using magnetic field due to straight wire :

$B = \frac{μ_{0} i}{4 π r} (s i n α + s i n β)$

$= \frac{1 0^{- 7} \times 1.5}{(\frac{0.09}{2 \sqrt[]{3}})} \times (s i n 60 ° + s i n 60 °) = 1 0^{- 5} T$

So, magnetic field due to three wires

= 3 × 10^-5 T

inside the plane

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A current of 1.5 A is flowing through a triangle, of side 9cm each. The magnetic field at the centroid of the triangle is:

(Assume that the current is flowing in the clockwise direction.)

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A current of 1.5 A is flowing through a triangle, of side 9cm each. The magnetic field at the centroid of the triangle is: (Assume that the current is flowing in the clockwise direction.)

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A current of 1.5 A is flowing through a triangle, of side 9cm each. The magnetic field at the centroid of the triangle is:

(Assume that the current is flowing in the clockwise direction.)