A cycle followed by an engine (made of one mole of an ideal gas in a cylinder with a piston) is shown in Fig.. Find heat exchanged by the engine, with the surroundings for each section of the cycle. (Cv = (3/2) R)

AB : constant volume

BC : constant pressure

CD : adiabatic

DA : constant pressure 

3 Views|Posted 7 months ago
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7 months ago

This is a long answer type question as classified in NCERT Exemplar

(a) For process AB

Volume is constant , hence work done dW=0

dQ=dU+dW=dU+0=dU

 = nCvdT= nCv(TB-TA)

 = 3 2 R T B - T A

= 3 2 R T B - R T A = 3 2 P B V B - P A V A

Heat exchanged = 3 2 P B V B - P A V A

(b) For process BC , p =constant

dQ= dU+dW  = 3 2 R T C - T B + P B ( V C - V B )

heat exchanged = 5 2 P B ( V C - V A )

(c) For process CD , because CD is adiabatic

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physics ncert solutions class 11th 2023

physics ncert solutions class 11th 2023

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