A cyclist starts from centre O of a circular park of radius 1km and moves along the path OPRQO as shown Fig. 4.3. If he maintains constant speed of 10ms–1, what is his acceleration at point R in magnitude and direction?
A cyclist starts from centre O of a circular park of radius 1km and moves along the path OPRQO as shown Fig. 4.3. If he maintains constant speed of 10ms–1, what is his acceleration at point R in magnitude and direction?
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1 Answer
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This is a Short Answer Type Questions as classified in NCERT Exemplar
Explanation- the cyclist covers OPRQO path.
As we know whenever an object performing circular motion, acceleration is called centripetal acceleration and is always directed towards the centre.
so there will be centripetal acceleration a= v2/r
So a= 100/1km= 100/1000=0.1m/s2 along RO.
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