A force of F = (5y + 20)ĵ acts on a particle. The work done by this force when the particle is moved from y = 0m to y = 10m is __________ J.
A force of F = (5y + 20)ĵ acts on a particle. The work done by this force when the particle is moved from y = 0m to y = 10m is __________ J.
Asked by Shiksha User
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1 Answer
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W = ∫Fxdy
W = ∫ (5y + 20)dy from 0 to 10
W = [5y²/2 + 20y] from 0 to 10
W = (5 (10)²/2 + 20 (10) - 0 = 250 + 200 = 450 J
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