A geostationary satellite is orbiting around an arbitrary planet 'P' at a height of 11R above the surface of 'P', R being the radius of 'P'. The time period of another satellite in hours at a height of 2R from the surface of 'P' is ---------. 'P' has the time period of 24 hours.
A geostationary satellite is orbiting around an arbitrary planet 'P' at a height of 11R above the surface of 'P', R being the radius of 'P'. The time period of another satellite in hours at a height of 2R from the surface of 'P' is ---------. 'P' has the time period of 24 hours.
Option 1 - <p>6√2</p>
Option 2 - <p>3</p>
Option 3 - <p>5</p>
Option 4 - <p>6/√2</p>
3 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
A
Answered by
5 months ago
Correct Option - 2
Detailed Solution:
(T / 24) = (3/12)^ (3/2) ⇒ T = 3 hours
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