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A heat engine is involved with exchange of heat of 1915 J, –40 J, +125 J and –QJ, during one cycle achieving and efficiency of 50.0%. The value of Q is:

Option 1 -

40 J

Option 2 -

640 J

Option 3 -

400 J

Option 4 -

980 J

0 3 Views | Posted 2 months ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    2 months ago
    Correct Option - 4


    Detailed Solution:

    Efficiency η = Q_net/Q? = (1915-40+125-Q)/ (1915+125) = 0.5.
    (2000-Q)/2040=0.5 ⇒ Q=980J.

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