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A helicopter rises from rest on the ground vertically upwards with a constant acceleration g. A food packet is dropped from the helicopter when it is at a height h. The time taken by the packet to reach the ground is close to [ g is the acceleration due to gravity]:

 

Option 1 -

t = 1.8 √(h/g)

Option 2 -

t = √(2h/3g)

Option 3 -

t = 3.4 √(h/g)

Option 4 -

t = (2/3) √(h/g)

0 2 Views | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    a month ago
    Correct Option - 3


    Detailed Solution:
    Kindly go through the solution

     

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