A helicopter rises from rest on the ground vertically upwards with a constant acceleration g. A food packet is dropped from the helicopter when it is at a height h. The time taken by the packet to reach the ground is close to [ g is the acceleration due to gravity]:
A helicopter rises from rest on the ground vertically upwards with a constant acceleration g. A food packet is dropped from the helicopter when it is at a height h. The time taken by the packet to reach the ground is close to [ g is the acceleration due to gravity]:
Option 1 - <p>t = 1.8 √(h/g)</p>
Option 2 - <p>t = √(2h/3g)</p>
Option 3 - <p>t = 3.4 √(h/g)</p>
Option 4 - <p>t = (2/3) √(h/g)<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
5 Views|Posted 5 months ago
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5 months ago
Correct Option - 3
Detailed Solution:
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