A hollow spherical shell at outer radius R floats just submerged under the water surface. The inner radius of the shell is r. If the specific gravity of the shell material is 27/8 w.r.t water, the value of r is.
A hollow spherical shell at outer radius R floats just submerged under the water surface. The inner radius of the shell is r. If the specific gravity of the shell material is 27/8 w.r.t water, the value of r is.
Option 1 -
2/3 R
Option 2 -
4/9 R
Option 3 -
1/3 R
Option 4 -
8/9 R
Asked by Shiksha User
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1 Answer
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Correct Option - 4
Detailed Solution:As it just floats B = mg
(4πR³/3) (ρ? ) (g) = (4πR³/3 - 4πr³/3) (ρ? ) (g)
R³ = (R³ - r³) (27/8)
On solving we get,
r = 8/9 R (approx)
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