A hydrogen atom in its ground state absorbs 10.2 eV of energy. The angular momentum of electron of the hydrogen atom will increase by the value of:
(Given, Planck’s constant = 6.6 × 10-34 Js).
A hydrogen atom in its ground state absorbs 10.2 eV of energy. The angular momentum of electron of the hydrogen atom will increase by the value of:
(Given, Planck’s constant = 6.6 × 10-34 Js).
Option 1 -
2.10 * 10-34Js
Option 2 -
Option 3 -
3.15 * 10-34Js
Option 4 -
4.2 * 10-34Js
-
1 Answer
-
Correct Option - 2
Detailed Solution:Given absorb energy = 10.2 eV
n = 2
Similar Questions for you
Change in surface energy = work done
|DE0| = –10.2

]
= 3 m/s
n = 4
Number of transitions =
Kinetic energy: Potential energy = 1 : –2
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 687k Reviews
- 1800k Answers