A juggler throws ball vertically upwards with same initial velocity in air. When the first ball reaches its highest positions he throws the next ball. Assuming the juggler throws n balls per second, the maximum height the balls can reach is

Option 1 - <p>g/2n&nbsp; &nbsp;&nbsp;</p>
Option 2 - <p>g/n</p>
Option 3 - <p>2gn</p>
Option 4 - <p>g/2n<sup>2</sup></p>
2 Views|Posted 6 months ago
Asked by Shiksha User
1 Answer
P
6 months ago
Correct Option - 4
Detailed Solution:

Time to reach at max height t = ugno. of balls thrown in 1 sec = n.

So, time taken by each ball to reach maxm height, = 1nsec

i.e. ug=1nu=gn So, hmax = u22g

g22gn2

=g2n2

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Physics Motion in Straight Line 2025

Physics Motion in Straight Line 2025

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