A juggler throws ball vertically upwards with same initial velocity in air. When the first ball reaches its highest positions he throws the next ball. Assuming the juggler throws n balls per second, the maximum height the balls can reach is
A juggler throws ball vertically upwards with same initial velocity in air. When the first ball reaches its highest positions he throws the next ball. Assuming the juggler throws n balls per second, the maximum height the balls can reach is
Option 1 - <p>g/2n </p>
Option 2 - <p>g/n</p>
Option 3 - <p>2gn</p>
Option 4 - <p>g/2n<sup>2</sup></p>
2 Views|Posted 6 months ago
Asked by Shiksha User
1 Answer
P
Answered by
6 months ago
Correct Option - 4
Detailed Solution:
Time to reach at max height t = of balls thrown in 1 sec = n.
So, time taken by each ball to reach maxm height, =
i.e. So, hmax =
=
Similar Questions for you
From A to B the process is isobaric

= W = 2 × R (600 - 350)
= 500 R
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else.
On Shiksha, get access to
66K
Colleges
|
1.2K
Exams
|
6.9L
Reviews
|
1.8M
Answers
Learn more about...

Physics Motion in Straight Line 2025
View Exam DetailsMost viewed information
SummaryDidn't find the answer you were looking for?
Search from Shiksha's 1 lakh+ Topics
or
Ask Current Students, Alumni & our Experts
Have a question related to your career & education?
or
See what others like you are asking & answering





