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A mass of 1 kg is suspended by a thread. It is lifted up with an acceleration of 4.9 ms–2, and then lowered with an acceleration of 4.9 ms–2 . The ratio of tensions in first case to second cases is (g = 9.8 ms–2 )

Option 1 -

2 : 1

Option 2 -

1 : 1

Option 3 -

3 : 1

Option 4 -

1 : 3

0 0 Views | Posted 3 hours ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    3 hours ago
    Correct Option - 3


    Detailed Solution:

    T1 = m (g  + a)

    T2 = m (g - a)

     

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