A mixture of hydrogen and oxygen has volume 2000 cm³, temperature 300K, pressure 100 kPa and mass 0.76g. The ratio of number of moles of hydrogen to number of moles of oxygen in the mixture will be:

[Take gas constant R = 8.3 JK^-¹ mol^-¹]

Option 1 -

$\frac{1}{3}$

Option 2 -

$\frac{3}{1}$

Option 3 -

$\frac{1}{16}$

Option 4 -

$\frac{16}{1}$

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Asked by Shiksha User

1 Answer

Answered by

Vishal Baghel | Contributor-Level 10

2 months ago

Correct Option - 2

Detailed Solution:

$V_{T} = 2000 c m^{3} = 2000 \times 1 0^{- 6} m^{3} (T o t a l v o l u m e o f m i x t u r e)$

T = 300 K

$_{}^{}^{}$ $P_{T} = 100 k P a = 100 \times 1 0^{3} P a = 1 0^{5}$ Pa

mT = 8.3 J/K1 mol1

Now, using Ideal gas equation

$P_{T} V = (x_{1} + x_{2}) R T$

$\Rightarrow 1 0^{5} \times 200 \times 1 0^{- 6} = (x_{1} + x_{2}) \times 8.3 \times 300$

$\frac{x_{1}}{x_{2}} = \frac{0.06}{0.02} = 3 : 1$

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A mixture of hydrogen and oxygen has volume 2000 cm³, temperature 300K, pressure 100 kPa and mass 0.76g. The ratio of number of moles of hydrogen to number of moles of oxygen in the mixture will be:

[Take gas constant R = 8.3 JK^-¹ mol^-¹]

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A mixture of hydrogen and oxygen has volume 2000 cm3, temperature 300K, pressure 100 kPa and mass 0.76g. The ratio of number of moles of hydrogen to number of moles of oxygen in the mixture will be: [Take gas constant R = 8.3 JK-1 mol-1]

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A mixture of hydrogen and oxygen has volume 2000 cm³, temperature 300K, pressure 100 kPa and mass 0.76g. The ratio of number of moles of hydrogen to number of moles of oxygen in the mixture will be:

[Take gas constant R = 8.3 JK^-¹ mol^-¹]