A mixture of hydrogen and oxygen has volume 500 cm3, temperature 300K, pressure 400 kPa and mass 0.76g. The ratio of masses of oxygen to hydrogen will be:-

Using Ideal gas Equation : PV = nRT ⇒ n = P V R T = 4 0 0 * 1 0 3 * 5 0 0 * 1 0 − 6 8 . 3 * 1 0 0 = 0 . 0 0 8 => m 1 = 0 . 1 2 , m 2 = 0 . 6 4 => m 2 m 1 = 1 6 3

A mixture of hydrogen and oxygen has volume 500 cm³, temperature 300K, pressure 400 kPa and mass 0.76g. The ratio of masses of oxygen to hydrogen will be:-

Option 1 - 3 : 16

Option 2 - 16 : 3

Option 3 - 3 : 8

Option 4 - 8 : 3

2 Views|Posted 6 months ago

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Answered by

Vishal Baghel | Contributor-Level 10

6 months ago

Correct Option - 2

Detailed Solution:

Using Ideal gas Equation :

PV = nRT

$\Rightarrow n = \frac{P V}{R T} = \frac{400 * 1 0^{3} * 500 * 1 0^{- 6}}{8.3 * 100} = 0.008$

=> $m_{1} = 0.12, m_{2} = 0.64$

=> $\frac{m_{2}}{m_{1}} = \frac{16}{3}$

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