A monochromatic neon lamp with wavelength of 670.5nm illuminates a photo-sensitive material which has a stopping voltage of 0.48V. What will be the stopping voltage if the source light is changed with another source of wavelength of 474.6nm?

Option 1 -

1.5V

Option 2 -

0.24V

Option 3 -

0.96V

Option 4 -

1.25V

3 Views | Posted 2 months ago

Asked by Shiksha User

1 Answer

Answered by

alok kumar singh | Contributor-Level 10

2 months ago

Correct Option - 4

Detailed Solution:

$e V_{S 2} = \frac{h c}{λ_{1}} - ?$

$e V_{S 2} = \frac{h c}{λ_{2}} - ?$

$e V_{S 2} - e V_{S 1} = \frac{h c}{λ_{2}} - \frac{h c}{λ_{1}}$

$\Rightarrow V_{S 2} = 0.48 + 12.43 \times 1 0^{- 7} \times (\frac{1}{474.6} - \frac{1}{670.5}) \times 1 0^{- 9}$

= 1.25 V

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A monochromatic neon lamp with wavelength of 670.5nm illuminates a photo-sensitive material which has a stopping voltage of 0.48V. What will be the stopping voltage if the source light is changed with another source of wavelength of 474.6nm?

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