A neutron beam of energy E scatters from atoms on a surface with a spacing d = 0.1 nm. The first maximum intensity in the reflected beam occurs at θ= 30°. What is the kinetic energy E of the beam in eV?

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    Pallavi Pathak | Contributor-Level 10

    3 months ago

    Explanation- given d= 0.1nm,  ?  =300 and n=1

    According to bragg's law

    2dsin ?  ?

    2 *0.1*sin30=?

    ? =0.1nm=10-10

    ? =hmv=hp

    P=h/ ?   = 6.62*10-3410-10 = 6.62 *10-24 kgm/s

    k.E= 1/2mv2= 12m2v2m p22m = 0.21eV

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