A neutron beam of energy E scatters from atoms on a surface with a spacing d = 0.1 nm. The first maximum intensity in the reflected beam occurs at θ= 30°. What is the kinetic energy E of the beam in eV?
A neutron beam of energy E scatters from atoms on a surface with a spacing d = 0.1 nm. The first maximum intensity in the reflected beam occurs at θ= 30°. What is the kinetic energy E of the beam in eV?
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1 Answer
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Explanation- given d= 0.1nm, =300 and n=1
According to bragg's law
2dsin = n
2
P=h/ = = 6.62 kgm/s
k.E= 1/2mv2= = = 0.21eV
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