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A parallel beam of light of wavelength 900nm and intensity 100Wm-2 is incident on a surface perpendicular to the beam. The number of photons crossing 1cm2 area perpendicular to the beam in one second is:

Option 1 -

3 * 1018

Option 2 -

4.5 * 1016

Option 3 -

4.5 * 1017

Option 4 -

4.5 * 1020

0 2 Views | Posted 2 months ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    2 months ago
    Correct Option - 2


    Detailed Solution:

     E=I  A

    =100×1×10−4

    =10−2W

    E=nhcλ

    10−2=n?   ×6.64×10−34×3×108900×10−9

    n? =10−2×9×10−76.64×10−34×3×108

    n? =4.5×1016

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