A parallel plate capacitor has plate of length ' l', width ' w ' and separation of plates is 'd '. It is connected to a battery of emf V . A dielectric slap of the same thickness 'd ' and of dielectric constant k = 4 is being, inserted between the plates of the capacitor. At what length of the slab inside plates, will be energy stored in the capacitor be two times the initial energy stored?
A parallel plate capacitor has plate of length ' l', width ' w ' and separation of plates is 'd '. It is connected to a battery of emf V . A dielectric slap of the same thickness 'd ' and of dielectric constant k = 4 is being, inserted between the plates of the capacitor. At what length of the slab inside plates, will be energy stored in the capacitor be two times the initial energy stored?
Before inserting slab
C_i = ε? A/d
After inserting dielectric slab
C_i = ε? lw/d
C_f = C? + C?
C_f = (Kε? A? /d) + (ε? A? /d)
C_f = 2C_i ⇒ (Kε? wx/d) + (ε? w (l-x)/d) = 2ε? lw/d
4x + l - x = 2l
x = l/3
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