A parallel plate capacitor is charged by connecting it to a battery through a resistor. If is the current in the circuit, then in the gap between the plates:
A parallel plate capacitor is charged by connecting it to a battery through a resistor. If is the current in the circuit, then in the gap between the plates:
Option 1 - <p><span lang="EN-IN">There is no current</span></p>
Option 2 - <p><span lang="EN-IN">Displacement current of magnitude equal to <span class="mathml" contenteditable="false"> <math> <mrow> <mi>I</mi> </mrow> </math> </span>flows in the same direction as <!-- [if gte vml 1]><v:shape
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Option 3 - <p><span lang="EN-IN">Displacement current of magnitude equal to <span class="mathml" contenteditable="false"> <math> <mrow> <mi>I</mi> </mrow> </math> </span> flows in a direction opposite to that of <!-- [if gte vml 1]><v:shape id="_x0000_i1026" type="#_x0000_t75"
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Option 4 - <p><span lang="EN-IN">Displacement current of magnitude greater than / flows but can be in any direction</span></p>
5 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
A
Answered by
5 months ago
Correct Option - 2
Detailed Solution:

According to modified Ampere's law
For Loop and
For Loop and
Due to
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->R3 = (R + x)2 (R – x)
->R3 = (R2– x2) (R + x)
->x2 + Rx – R2 = 0
R is not correct.
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