A parallel plate capacitor is charged by connecting it to a battery through a resistor. If $I$  is the current in the circuit, then in the gap between the plates:

Correct Option - 2


Detailed Solution:

According to modified Ampere's law

$?B.dI={\mu }_0\left(I_C+I_D\right)$

For Loop  $L_1{I}_C\ne 0$ and $I_D=0$

For Loop  $L_2{I}_C=0$ and $I_D\ne 0$

Due to  $KCL{I}_C=I_D$

<div><div><picture><source srcset="" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/1754992677phpCZkUbn.jpeg" alt="" width="463" height="139" loading="lazy"></picture></div></div><p><span lang="EN-IN">According to modified Ampere's law</span></p><p><span lang="EN-IN"><span contenteditable="false"> <math> <mrow> <mo>? </mo> <mi>B</mi> <mo>.</mo> <mi>d</mi> <mi>I</mi> <mo>=</mo> <msub> <mrow> <mi>μ</mi> </mrow> <mrow> <mn>0</mn> </mrow> </msub> <mrow> <mo> (</mo> <mrow> <msub> <mrow> <mi>I</mi> </mrow> <mrow> <mi>C</mi> </mrow> </msub> <mo>+</mo> <msub> <mrow> <mi>I</mi> </mrow> <mrow> <mi>D</mi> </mrow> </msub> </mrow> <mo>)</mo> </mrow> </mrow> </math> </span><br>&lt;!--- [endif]---&gt;&lt;!--- [if gte mso 9]--&gt; &lt;!-- [endif]---&gt;</span></p><p><span lang="EN-IN">For Loop&nbsp;<span contenteditable="false"> <math> <mrow> <msub> <mrow> <mi>L</mi> </mrow> <mrow> <mn>1</mn> </mrow> </msub> <msub> <mrow> <mi>I</mi> </mrow> <mrow> <mi>C</mi> </mrow> </msub> <mo>≠</mo> <mn>0</mn> </mrow> </math> </span> and <span contenteditable="false"> <math> <mrow> <msub> <mrow> <mi>I</mi> </mrow> <mrow> <mi>D</mi> </mrow> </msub> <mo>=</mo> <mn>0</mn> </mrow> </math> </span>&lt;!--- [endif]---&gt;&lt;!--- [if gte mso 9]--&gt; &lt;!-- [endif]---&gt;</span></p><p><span lang="EN-IN">For Loop&nbsp;<span contenteditable="false"> <math> <mrow> <msub> <mrow> <mi>L</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msub> <msub> <mrow> <mi>I</mi> </mrow> <mrow> <mi>C</mi> </mrow> </msub> <mo>=</mo> <mn>0</mn> </mrow> </math> </span> and <span contenteditable="false"> <math> <mrow> <msub> <mrow> <mi>I</mi> </mrow> <mrow> <mi>D</mi> </mrow> </msub> <mo>≠</mo> <mn>0</mn> </mrow> </math> </span>&lt;!--- [endif]---&gt;&lt;!--- [if gte mso 9]--&gt; &lt;!-- [endif]---&gt;</span></p><p><span lang="EN-IN">Due to&nbsp;<span contenteditable="false"> <math> <mrow>KCL<msub><mrow><mi>I</mi></mrow><mrow><mi>C</mi></mrow></msub><mo>=</mo><msub><mrow><mi>I</mi></mrow><mrow><mi>D</mi></mrow></msub></mrow> </math> </span>&lt;!--- [endif]---&gt;&lt;!--- [if gte mso 9]--&gt; &lt;!-- [endif]---&gt;</span></p>

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