A parallel plate capacitor of capacitance 200
is connected to a battery of 200V. A dielectric slab of dielectric constant 2 is now inserted into the space between plates of capacitor while the battery remain connected. The change in the electrostatic energy in the capacitor will be_______J.
A parallel plate capacitor of capacitance 200 is connected to a battery of 200V. A dielectric slab of dielectric constant 2 is now inserted into the space between plates of capacitor while the battery remain connected. The change in the electrostatic energy in the capacitor will be_______J.
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1 Answer
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Battery is connected while dielectric is inserted so potential difference will be remains same.
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