A particle is attached to the lower end of a uniform rod which is hinged at its other end as shown in the figure. Another identical particle moving horizontally, collides inelastically and sticks to it. The minimum speed of moving particle so that the rod with particles performs circular motion in a vertical plane will be: [length of rod is l ,  consider masses of both particles and rod to be same]

 

Option 1 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mroot> <mrow> <mn>1</mn> <mn>0</mn> <mi>g</mi> <mi mathvariant="script">l</mi> </mrow> <mrow></mrow> </mroot> </mrow> </math> </span></p>
Option 2 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mroot> <mrow> <mn>2</mn> <mn>0</mn> <mi>g</mi> <mi mathvariant="script">l</mi> </mrow> <mrow></mrow> </mroot> </mrow> </math> </span></p>
Option 3 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mroot> <mrow> <mfrac> <mrow> <mn>7</mn> <mn>0</mn> </mrow> <mrow> <mn>3</mn> </mrow> </mfrac> <mi>g</mi> <mi mathvariant="script">l</mi> </mrow> <mrow></mrow> </mroot> </mrow> </math> </span></p>
Option 4 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mroot> <mrow> <mfrac> <mrow> <mn>1</mn> <mn>7</mn> <mn>5</mn> </mrow> <mrow> <mn>3</mn> </mrow> </mfrac> <mi>g</mi> <mi mathvariant="script">l</mi> </mrow> <mrow></mrow> </mroot> </mrow> </math> </span></p>
46 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
A
5 months ago
Correct Option - 3
Detailed Solution:

From conservation of Angular momentum about hinged point

m v l = ( m l 2 3 + 2 m . l 2 ) ω            

ω = ( 3 7 v l )            

Now from conservation of Energy.

1 2 * 7 3 m l 2 * ω 2 = m g l + 2 m g . 2 l            

v = 7 0 3 g l            

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physics ncert solutions class 11th 2023

physics ncert solutions class 11th 2023

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