A particle is moving along the x  -axis with its coordinate with time ' t  ' given by x ( t ) = 10 + 8 t - 3 t 2  . Another particle is moving along the  y -axis with its coordinate a function of time given by y ( t ) = 5 - 8 t 3  . At t = 1 s  , the speed of the second particle as measured in the frame of the first particle is given as v  . Then v  (in  ) m / s is

2 Views|Posted 5 months ago
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1 Answer
R
5 months ago

580

X 1 = - 3 t 2 + 8 t + 10

v ? 1 = ( - 6 t + 8 ) i ˆ = 2 i ˆ

Y 2 = 5 - 8 t 3

v ? 2 = - 24 t 2 j ˆ

v = v ? 2 - v ? 1 = | - 24 j ˆ - 2 i ˆ |

v = 24 2 + 2 2

v = 580

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Physics NCERT Exemplar Solutions Class 12th Chapter Fifteen 2025

Physics NCERT Exemplar Solutions Class 12th Chapter Fifteen 2025

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