A particle is moving in a straight line such that its velocity is increasing at 5 ms^-1 per meter. The acceleration of the particle is _________ms^-2 at a point where its velocity is 20 ms^-1.

 $tan\theta =\frac{dv}{dx}=5\left(m/s\right)/m$

$\Rightarrow dv=5dx\Rightarrow \frac{dv}{dt}=5\frac{dx}{dt}$

$\Rightarrow a=5v=5\times 20=100m/s^2$

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