A particle is moving with uniform speed along the circumference of a circle of radius of radius R under the action of a central fictitious force F which is inversely proportional to R3. Its time period of revolution will be given by

Option 1 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mi>T</mi> <mtext> </mtext> <mtext> </mtext> <mi>α</mi> <mtext> </mtext> <mtext> </mtext> <msup> <mrow> <mi>R</mi> </mrow> <mrow> <mfrac> <mrow> <mn>3</mn> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> </mrow> </msup> </mrow> </math> </span></p>
Option 2 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mi>T</mi> <mtext> </mtext> <mtext> </mtext> <mi>α</mi> <mtext> </mtext> <mtext> </mtext> <msup> <mrow> <mi>R</mi> </mrow> <mrow> <mfrac> <mrow> <mn>5</mn> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> </mrow> </msup> </mrow> </math> </span></p>
Option 3 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mi>T</mi> <mtext> </mtext> <mtext> </mtext> <mi>α</mi> <mtext> </mtext> <mtext> </mtext> <msup> <mrow> <mi>R</mi> </mrow> <mrow> <mfrac> <mrow> <mn>4</mn> </mrow> <mrow> <mn>3</mn> </mrow> </mfrac> </mrow> </msup> </mrow> </math> </span></p>
Option 4 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mi>T</mi> <mtext> </mtext> <mtext> </mtext> <mi>α</mi> <mtext> </mtext> <mtext> </mtext> <msup> <mrow> <mi>R</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msup> </mrow> </math> </span></p>
5 Views|Posted 6 months ago
Asked by Shiksha User
1 Answer
P
6 months ago
Correct Option - 4
Detailed Solution:

F=kR3=mv2Rv=kmR2=km*1R

T=2πRv=2πRkm* (1R)TαR2

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Physics Motion in Plane 2025

Physics Motion in Plane 2025

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